J.R. S. answered 02/08/18
Tutor
5.0
(145)
Ph.D. in Biochemistry--University Professor--Chemistry Tutor
You can graph the data or you can use the Arrhenius equation where ln (k2/k1) = -Ea/R(1/T2 - 1/T1) and solve for Ea.
Be sure to use K in Kelvin and R = 8.314 J/K-mole.
The graphical method would be to plot ln k as a function of 1/T and the slope would be equal to Ea/R, but with only 3 data points, your graph may not be the best.