
Francisco P. answered 08/28/14
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Rigorous Physics Tutoring
Let c = 10 and d = 5. We cut squares of length x from the corners, then
the length of the box is l = c - 2x,
the width of the box is w = d - 2x, and
the height of the box is h = x.
V = lwh = (c - 2x)(d - 2x)(x) = (10 - 2x)(5 - 2x)x
The volume of the box is positive and it is not possible to cut squares of lengths that are more than d/2 or 5/2. So the domain for the volume or the possible values of x is (0,5/2). a = 0 and b = 5/2.
V = lwh = (c - 2x)(d - 2x)(x) = (10 - 2x)(5 - 2x)x
The volume of the box is positive and it is not possible to cut squares of lengths that are more than d/2 or 5/2. So the domain for the volume or the possible values of x is (0,5/2). a = 0 and b = 5/2.