If 100 grams of dextrose is ordered using a 50% dextrose solution, how many mL are needed?

Question

Can someone show me how to do this.  My professor is making us do these problems and not showing us how to figure them out.  

Answer 1

I thought I answered this already, but here it is again.

50% solution should be identified as mass/volume or mass/mass, but we'll assume it is mass/volume (m/v) which it usually is for a dextrose (glucose) solution.  

Definition of % (m/v) = grams/100 ml of solution.  So, a 50% solution means 50 grams dextrose in 100 ml of solution.

If you need 100 g of dextrose, obviously you need 200 ml since 50 g is in 100 ml.  Mathematically, this is done as follows:

50 g/100 ml = 100 g/x ml

50x = 10000

x = 200 ml