
Paul H. answered 12/31/17
Tutor
4.9
(290)
SAT Math: strategies and content review!
Set a=WX; b=XY=8; and c=YZ
Since WY = WX + XY, we know that (a + 8) is to 2, as c is to 1
2 a + 8
--- = ------
1 c
So, 2c = a + 8, which means that c = 0.5a + 4
Since XZ = XY + YZ = 8 + (0.5a + 4), we know that a is to 2 as (0.5a + 12) is to 3
2 a
--- = ---------------
3 (0.5a + 12)
which means that 3a = a + 24
So, 2a = 24, and a = 12
So, WX = a = 12; XY = 8; and YZ = c = 0.5(12) + 4 = 10
Since WY = WX + XY, we know that (a + 8) is to 2, as c is to 1
2 a + 8
--- = ------
1 c
So, 2c = a + 8, which means that c = 0.5a + 4
Since XZ = XY + YZ = 8 + (0.5a + 4), we know that a is to 2 as (0.5a + 12) is to 3
2 a
--- = ---------------
3 (0.5a + 12)
which means that 3a = a + 24
So, 2a = 24, and a = 12
So, WX = a = 12; XY = 8; and YZ = c = 0.5(12) + 4 = 10
Paul H.
12/31/17