
Kenneth S. answered 11/21/17
Tutor
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(62)
Algebra II EXPERT will help you survive & prosper
You provided two zeros in the indicated table. One at x= -1, the other at x=1. At the first one, the graph crosses through the point (in an increasing way thru the zero) but at the second one, the graph appears to only be tangent to the x-axis at x=1, but is positive to the immediate left & to the immediate right of this 'touching' point.
I conclude that the polynomial is of degree three. This assumes that no zeros failed to be listed in the table.
In fact, the polynomial is f(x) = a(x+1)(x-1)2 and a is positive. It shouold be possible to figure out "a.