calculate the molarity of the two solutions.

Question

1) 0.550 mol of NaOH in 2.35 L solution

2) 10.9 g of NaCl in 887 mL of solution

Answer 1

M = molarity = moles/liter

 

(1)

 

M = (0.550 moles)/(2.35 L) = ? moles/L

 

(2)

 

Look up the atomic weights of Na and Cl in grams per mole, and add them to get the molecular weight of NaCl.  Divide 10.9 g of NaCl by the molecular weight of NaCl.  That gives the number of moles of NaCl.  Divide the number of moles of NaCl by the volume, which is 887 x 10^-3 L.  That gives the molarity.

 

Use this procedure to answer some similar problems that you posted.

Answer 2

0.55 moles NaOH = moles

2.35 L = liters of solution

Molarity = moles/liters of solution

 

10.9 g NaCl can be converted to moles by dividing by molar mass of NaCl.  Then you'll have moles.

887 ml of solution = 0.887 liters of solution

Molarity = moles/liters of solution