a sample of an ideal gas has a volume of 2.25 L at 288 K and 1.06 atm. Calculate the pressure when the volume is 1.07 L and the temperature is 3.00 x 10^2 K.

Question

in atm. chapter 7 chemistry 121

Answer 1

Using the combined gas law P₁V₁/T₁ = P₂V₂/T₂

First, be sure all the units are what you want them to be.  Convert the 3.00x10² K to 300 K to keep it simple.

Then plug in the values:

(1.06 atm)(2.25 L)/288 K = (P₂)(1.07 L)/300 K and solve for P₂

P₂ = (1.06 atm)(2.25 L)(300 K)/(288 K)(1.07 L) = answer.  Hopefully you can do the math.