a hot air ballon is filled with 1.27 x 10^6 L of an ideal gas on a cooling morning (11 degrees C). the air is heated to 121 degrees C.

Question

What is the volume of the air in the ballon after it is heated? assume that none of the gas escapes from the ballon 

Answer 1

Ah...another gas law problem.

You are given a volume of 1.27x10⁶ L and a temperature of 11ºC (284 K). You are then given a second condition with a different temperature of 121ºC (394 K) and asked for a new volume.  Since no pressure is given in this problem, it must be assumed to be constant.  Thus, you are dealing with Charles' Law.  V₁/T₁ = V₂/T₂   (Be sure to use K as the temp)

1.27x10⁶ L/284 K = V₂/394 K

V₂ = (1.27x10⁶ L)(394 K)/(284 K) = answer  (hopefully you can do the math)