Can you help me with this partial pressures problem?

Question

5.0g of SO2 and 5.0g of CO2 are placed in a 750mL container at 50°C. How do I calculate partial pressure of the SO2?

Answer 1

The partial pressure of SO2 is simply the pressure exerted by SO2 as if it were the only gas present.  Thus...

5.0 g SO2 x 1 mole SO2 x 64 g = 0.0781 moles SO2

From PV = nRT and solving for P, you get P = nRT/V

P = (0.0781 moles)(0.0821 Latm/Kmol)(323 K)/0.750 L

P = 2.76 atm = partial pressure of SO2