
Mark M. answered 10/12/17
Tutor
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Mathematics Teacher - NCLB Highly Qualified
r : y :: 3 : 4
4r = 3y
r - 3 : y - 6 :: 4 : 5
5(r - 3) = 4(y - 6)
5r - 15 = 4y - 24
4r - 3y = 0
5r - 4y = -9
Can you solve the system?