Raymond B. answered 10/14/19
Math, microeconomics or criminal justice
Let y = the speed of the water. Let x=his speed when rowing in still water.
distance = speed times time traveled d=st or s=d/t
He rowed downstream in 2 hours going 22 miles. That's d/t=22/2 = 11 mph = x+y
He rowed upstream in 5.5 hours doing the same 22 miles. That's d/t=22/5.5 mph = 2/.5 = 4 mph
4mph=x-y
you have 2 equations 2 unknowns, solve for one of the unknowns, x
x+y=11
x-y=4 add the 2 equations to eliminate y, getting
2x =15
x=15/2=7 1/2 mph
y=11-x=11-7.5=3.5 mph