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F(a) = log(1+a)/(1-a) then f(2a/(1+a2) = ?

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SURENDRA K. | An experienced,patient & hardworking tutorAn experienced,patient & hardworking tut...
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f(2a/(1+a^2)= log[(1+2a/(1+a^2))/(1-2a/(1+a^2) ]
 
                    = log[(1+a^2+2a)/(1+a^2-2a)]
 
                    = log[(1+a)^2)/(1-a)^2)]
 
                     =log[(1+a)/(1-a)]^2
 
                     = 2 log[(1+a)/(1-a)]
 
Well,I assume that symbols F & f are same in your question.