Peter L.
asked 01/16/135 years ago Gita was three times the age of his cousin Dilip. If Dilip is 8 years younger than Gita. How old is Gita now?
5 years ago Gita was three times the age of his cousin Dilip. If Dilip is 8 years younger than Gita. How old is Gita now?
2 Answers By Expert Tutors
Bill F. answered 01/16/13
Experienced Teacher & Tutor in Round Rock, TX
Let's let G = Gita's age now, and D = Dilip's age now
5 years ago, Gita was G-5 and Dilip was D-5
5 years ago, Gita was three times Dilip's age, which was D-5, so
G-5 = 3(D-5), or
G - 5 = 3D - 15, and
G = 3D - 15 + 5, or
G = 3D - 10
Now (this year), Gita is 8 years older than Dilip, or
G = D + 8, or
D = G - 8
Let's substitute D = G - 8 into the first equation:
G = 3(G-8) - 10, or
G = 3G - 24 - 10, or
G -3G = -34 and
-2G = -34, or
2G = 34, so
G = 17, Gita's current age.
Dilip is 8 years younger, so he is 17-8 = 9
Five years ago, Gita was 17-5 = 12, and Dilip was 9-5 = 4, so five years ago Gita was three times older than Dilip.
Chaitali M. answered 01/16/13
An Experienced Tutor in Elementary to College level Maths/Science.
Let Dilip's present age = x
Gita's present age = x + 8
5 yrs ago
3 (x-5) = (x+8)-5
3x - 15 = x + 3
2x = 18 , x = 9
Gita's present age = 17 yrs
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Herb K.
let G = Gita's age now, and let D = Dilip's age now;
then 5 years ago, Gita's age was G - 5, and Dilip's age was D - 5;
so that, G - 5 = 3(D - 5);
also, D = G - 8;
in which case, D - 5 = G - 8 - 5 = G - 13;
in which case, G - 5 = 3(G - 13);
in which case, G - 5 = 3G - 3*13
or, G -5 = 3G - 39;
or, 3G - 39 = G - 5;
now, subtracting G from each of the equation ---> 2G - 39 = - 5
then, adding 39 to each side of the equation ---> 2G = 39 - 5 ---> 2G = 34
or, dividing each side of the equation by 2 ---> G = 34/2 ---> G = 17 (Gita's age now)
01/17/13