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Question

Please help me answer this equation 

 

(X^2-3)(x^2+3x-4)=0

Answer 1

good morning Kingsley:  The question is asking you to find the value of x that makes the equation equal to zero. This is the same thing as asking where does the graph cross the x-axis.  

 

Since you have to parts (two things in parenthesis) set each equal to zero: 

x^2 -3 = 0  and solve for x. Remember when you take the square root of 3 you will have a positive and a negative answer!

 

x^2 +3 -4 = 0  and solve for x by factoring into two parts (x+4)(x-3) and set each of these equal to zero. 

 

Does that make sense?  

 

You will have four answers or four places the graph crosses the x-axis. 

Ms. J