Please help me answer this equation

(X^2-3)(x^2+3x-4)=0

Please help me answer this equation

(X^2-3)(x^2+3x-4)=0

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Wayzata, MN

good morning Kingsley: The question is asking you to find the value of x that makes the equation equal to zero. This is the same thing as asking where does the graph cross the x-axis.

Since you have to parts (two things in parenthesis) set each equal to zero:

x^2 -3 = 0 and solve for x. Remember when you take the square root of 3 you will have a positive and a negative answer!

x^2 +3 -4 = 0 and solve for x by factoring into two parts (x+4)(x-3) and set each of these equal to zero.

Does that make sense?

You will have four answers or four places the graph crosses the x-axis.

Ms. J

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