Philip P. answered • 06/08/14

Affordable, Experienced, and Patient Algebra Tutor

4x-37=-13

**-1 = x**

**y = 3**

Isabella A.

06/08/14

Philip P.

06/08/14

Philip P.

06/08/14

Stephen W.

06/08/14

Philip P.

06/08/14

Stephen W.

06/08/14

Isabella A.

asked • 06/08/143x+4y=9

4x-37=-13

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Philip P. answered • 06/08/14

Affordable, Experienced, and Patient Algebra Tutor

3x+4y=9

4x-37=-13

4x-37=-13

OK, you did write the equations down incorrectly. They should be:

3x+4y = 9

4x-3y = -13

Let's re-write them in standard form y = mx+b

3x+4y = 9

4y = 9 - 3x

y = (9/4) - (3/4)x

4x-3y=-13

-3y = -13 - 4x

y = (13/3) + (4/3)x

Now set the two equations equal. This is the point where the two lines intersect:

(9/4) - (3/4)x = (13/3) + (4/3)x

(9/4) - (13/3) = (4/3)x + (3/4)x

-25/12 = (25/12)x

Solve for y by plugging x = -1 into either original equation:

3x + 4y = 9

3(-1) + 4y = 9

-3 + 4y = 9

4y = 12

Answer is (-1,3)

Isabella A.

see the answers could only be

A. (-1,-3)

B. no solution

C. infinitely many solutions

D. (-1,3)

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06/08/14

Philip P.

Oops, I plugged in x=3 instead of x=6, so the y value is -9/4 vice 0.

Since (6,-9/4) is not one of the options, did you write the equations down correctly?

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06/08/14

Philip P.

You did write the equations down incorrectly - the second equation should be 4x-3y=-13 vice 4x-37=-13. I've corrected the answer above.

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06/08/14

Stephen W.

tutor

LOL! You are more patient than I am. I noticed that, and decided to step away from this problem. Lots of time wasted.

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06/08/14

Philip P.

You were probably the wiser one of the two of us. That second equation - without a y term - was suspect. But once I made the mistake of stepping in, I needed to try to figure it out. ;-)

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06/08/14

Stephen W.

tutor

Bravo! I admire your dedication.

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06/08/14

Stephen W. answered • 06/08/14

Othello, Eltopia, Connell, Pasco, West Pasco - I am in your area!

Are you supposed to use substitution, elimination or graphing?

Isabella A.

Graphing

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06/08/14

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Isabella A.

06/08/14