How do i calculate current (I) for the circuit shown.

Question

http://s26.postimg.org/3tm200jkp/image020.jpg

Answer 1

Using KVL rule, V=Vr + Vc Vr=I*R=I*2.2*10^3=2200I Vc=I*Xc = I*225.75=225.75I {Xc=1/wc=1/(2*Pi*f*C)=1/(2*pi*15000*47*10^(-9))=1/0.004429646} Now 12=2200I+225.75I 2425.75I=12 I=12/2425.75 =0.0049Amp= 4.9mA