
Bob A. answered 05/09/14
Tutor
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a) (f o g)(x) means f(g(x))
so what you do is substitute g(x) into f(x) for x
(f o g)(x) = f(g(x)) = 4[g(x)]2-6 = 4[x-2]2 - 6 = 4[x2-4x+4] -6
= 4x2 - 16x + 16 -6 = 4x2 - 16x + 10
for b) (f o g) (-1) means evaluate (f o g) for x = -1
so (f o g) (-1) = 4x2 - 16x + 10 where x = -1
I think you can substitute in the -1 and take it from there.
If not, let us know where you got stuck.