calculate please

Question

Calculate and show work 

 

a) 5[3-8*3^2+4*6-2]

 

b) [4(8-6)^2 +4](3-2*8)

         2^2(2^3+5)

Answer 1

You need to follow the "order of operations", PEMDAS:

 

P = Parentheses

E = Exponents

M = Multiplications

D = Divisions

A = Additions

S = Subtractions

 

a) 5[3-8*3^2+4*6-2]   (First we need to do all operations in the brackets (parentheses))

 

= 5[3-8*9+4*6-2]      (Exponents 3² = 9) 

= 5[3-72+24-2]          (Multiplications 8*9 = 72, 4*6=24)

= 5[3-96-2]                (No divisions, so next is additions: 72+24=96)

= 5[-95]                     (Subtractions: 3-96 = -93, -93-2 = -95)

= -475                (Now multiply the 5 outside the bracket by the result (-95) inside the bracket)

 

b) Works the same as a) but involves a division.  Do the numerator first, then the denominator, then divide the numerator by the denominator last.