Carroll bikes 1 kilometer east,4 kilometers north, and then 5 kilometers east again. How far is Carroll from her starting position?

Question

help pleas eand fast i have so much to get through

Answer 1

Starting at point (0,0) on a coordinate system of axis, Carrol bike 1km east and her new position is ( 0+1,0) = ( 1,0), 4 kilometers north and her position is (1,0+4) = (1,4), and 5 kilometer east again and her final position is ( 1+5,4) =(6,4)

 

The distance between her staring poin and ending point is the straight line that joins the two points ( 0,0) and ( 6,4)

 

That distance is the hypotenuse of the right angle triangle formed with the points

 

(0,0),(6,0), and (6,4)

 

the distance is = √(4-0)²+(6-0)² = √16+36 = √52= 7.2km