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How do you solve (2^-3)^-3

numbers with negative exponents and parentheses both addition and multiplication of the base numbers in parentheses and with combinations of positive and negative exponenets outside the parentheses.

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1 Answer

(2-3)-3     Given

2(-3)(-3)    When taking a power of a power, multiply the exponants

29           Substitution (-3 X -3 = 9)

512         Substitution (29 = 512)

 

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