Algebra problem solving

Question

how do you solve this problem? 2k^2+7k+3

Answer 1

to factor the given expression

this is in the form ax^2 + bx + c

find a*c then use factors of ac that add up to b also pay attention to the signs.

express the middle term with the terms added

regroup and factor out what is common

 

2k^2+7k+3

a = 2; b = 7 and c = 3

ac = 6 what are the factors of 6 that add up to 7? use +6 and +1

2k^2 + 6k + k + 3

group and factor

2k^2 + 6k and k + 3

2k(k+3) + 1(k + 3)  here k + 3 is common to both groups

(2k + 1)(k + 3)

 

Answer 2

I am guessing that the question here is to factor the given expression:

 

2k^2+7k+3

 

Let us set this up as the multiplication of two binomials:

 

We have two possibilities:

A: (2k + 3) (k + 1)

 

or

 

B: (2k + 1) (k + 3)

 

For the first possible solution (A), the k-term will work out to be (2k)(1) + 3(k) = 5k which is not the middle term of the starting expression so this does not look good.

 

For the Second possible solution (B), the k-term will work out to be (2k)(3) + 1(k) = 7k which is the middle term of the starting expression so this is the answer: (2k + 1) (k + 3)

 

 

Answer 3

That's not a problem; it's an expression.

 

An expression can't be solved.

 

What do you need to do with it?