Prashanth C. answered 08/22/23
Great students never forget their tutors
To determine the sample size needed to estimate the percentage of left-handed people with a 99% confidence level and a margin of error of 3 percentage points, you can use the formula for sample size calculation:
n = (Z2.p(1-p))/E2
Where:
n is the required sample size
Z is the Z-score corresponding to the desired confidence level (for 99% confidence level, Z is approximately 2.576)
p is the estimated proportion of the population that is left-handed (since we don't know this, we can use p =0.5 for maximum variability)
E is the desired margin of error (3 percentage points, so E =0.03)
Plugging in the values:
n = ((2.576)20.5(1-0.5))/(0.03)2
≈1776.52
So, you would need to survey around 1777 people in order to be 99% confident that your estimate of the percentage of left-handed people is within 3 percentage points of the population percentage.