
Kemal G. answered 05/09/17
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Patient and Knowledgeable Math and Science Tutor with PhD
Hi Lilly,
2x^3y + 8xy - 4x^2y - 16y
write it like this
2x^3y - 4x^2y + 8xy - 16y (I shuffled the terms to bring similar terms together, which will help with factoring)
2x^2y(x - 2) + 8y(x - 2) (I factored the first two and the last two terms, respectively). This is the answer to Part A.
You can see that (x - 2) is a common factor. We can use that to completely factor the expression.
(x - 2)(2x^2y + 8y) This is the answer to Part B.
Ember S.
Is "(x-2)" also the same as -2y? Because not all of the terms have an x but all of them have ys. For the first part I got 2y(x3+4x–2x2-8). I don't know how to do the second part because it has 4 terms and I only know how to do trinomials and binomials.... But I'm still not sure your answer is right.....┐( ∵ )┌05/21/20