b/sin(120) = 29/sin(10)
bsin(10) = 29sin(120)
b = 29sin(120)/sin(10)
carmen J.
asked • 05/07/17The problem refers to an ABC triangle
The problem refers to an ABC triangle if B=120 degrees and C=10 degrees and c=29 find b.
I did law of sines and got b= 144 but that is the wrong answer help with steps please. I did (29)/sin(10degrees) x sin(120degrees).
I did law of sines and got b= 144 but that is the wrong answer help with steps please. I did (29)/sin(10degrees) x sin(120degrees).
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2 Answers By Expert Tutors
Michael J. answered • 05/07/17
Tutor
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(5)
Applying SImple Math to Everyday Life Activities
b / sinB = c / sinC
Cross-multiply.
bSinC = cSinB
b = cSinB / SinC
b = (29 * Sin120) / Sin10
Also, make sure your calculator is set to degrees. Otherwise you will get incorrect values.
carmen J.
I still get 144 as the answer but it is not an answer choice
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05/07/17
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carmen J.
05/07/17