
David W. answered 04/24/17
Tutor
4.7
(90)
Experienced Prof
(a) What is the weight of the dried mushrooms if all the water were to be removed?
The weight of the water is 92% of the total weight. [note: 92% may be written as (92/100) or o.92 as needed by the problem.]
(92/100)*5 = 4.60 kg
Weight of mushrooms = 5 kg - 4.60 kg - 0.40 kg
(b) What is the weight of the mushrooms at a stage when they are partially dried and the amount of water is 60% of the total weight?
Total weight = (weight of water) + (weight of dried mushrooms)
Total weight = (60/100)(total weight) + (weight of dried mushrooms)
(40/100)(Total weight) = 0.40 kg
(Total weight) = 1 kg [note: 0.4 kg mushrooms and 0.6 kg (that is, 60%) water]