J.R. S. answered 04/18/17
Tutor
5.0
(145)
Ph.D. in Biochemistry--University Professor--Chemistry Tutor
Allegation:
HAVE WANT NEED
30%........................10.....
..............50%..................
60%.......................20......
So you need 10 parts of 30% and 20 parts of 60% for a total of 30 parts
30 parts = 90 liters, thus 1 part = 3 liters
10 parts x 3 liters/part = 30 liters of 30% + 60 liters of 60%
Done another way:
x = L of 30%
y = L of 60%
x + y = 90
(x)(30) + (y)(60) = 90 x 50 = 4500
x = 90-y
(90-y)(30) + 60y = 4500
2700 - 30y + 60y = 4500
30y = 1800
y = 60 liters of 60%
x = 30 liters of 30%