Patrick D. answered • 04/17/17

Tutor

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Patrick the Math Doctor

Distance = rate x time

They both travel the same distance.

Note that 2 and 1/4 = 2.25

rate for cat x time for cat = rate for mouse x time for mouse

5 x t = 2 x (t+ 2.25) <-- mouse travels 2.25 seconds longer than the cat

5t = 2(t+2.25)

5t = 2t + 4.5

3t = 4.5

t = 1.5 seconds

cat travels 5 m/sec x 1.5 sec = 7.5 meters

mouse travels 2m/sec x (1.5 +2.25) sec = 2 m/sec * 3.75 sec = 7.5 meters.

The cat will catch the mouse in 1.5 seconds.

Andrew M.

04/17/17