For a fixed value of d, this set is over determined. There are three equations but only two unknowns.
One approach is to solve the first two equations for x and y. This can be done by standard methods. The result is:
x = 1/16 y = -10/16
Plugging in these values of x and y into the third equation results in d = 55/16.
This is the only value of d for which the solution set for the three equations is not the empty set (that is no solution)
For d = 55/16 the graphs of the three lines all meet at x = 1/16, y = -10/16