J.R. S. answered 03/22/17
Tutor
5.0
(145)
Ph.D. in Biochemistry--University Professor--Chemistry Tutor
A - 102856.67 = 0.1493A
-102856.67 = 0.1493A - A = - 0.8507A
A = 120,908.27
14.93% of A = 0.1493 x 120,908.27 = 18,051.61