Howard L. answered • 02/04/17

Math Teacher/Tutor Specializing in Calculus I II III

Using conversion factor,

1.93 cal/(min x cm

^{2}) x (1 min/ 60 sec) x (10^{4}cm^{2}/ 1 m^{2}) x (1 KW x sec/ 239 cal) = 1.3458...Therefore,

**1.35 KW/m**^{2}