
Rebecca R. answered 02/20/14
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This can be done graphically and algebraically.
Algebraically, we know that the point they have given us (6,1) corresponds to a point on the coordinate system of (x,y). So, what they have given us is that x = 6 and y = 1.
To determine if the point is a solution, all you have to do is to plug the values into the equation:
2x - 4y = 7
2(6) - 4(1) = 7
12 - 4 = 7
8 = 7 Obviously, 8 does not equal 7, so we can see that the point is not a solution.
Graphically, we can show the same thing. For starters, we need to rearrange the equation to get it into point-slope form so it can easily be graphed.
2x-4y=7
-4y = 7-2x
y= 1/2(x) -7
Now you can see easily that the equation is a line of slope 1/2 which crosses the y axis at y=-7. If you graph such a line, you will clearly see that the point does not lie on it. You can also substitute the value of 6 for x into the equation. If the point lies on the line, then the value of y at x = 6 should be 1
y=1/2(6) - 7
y=3 -7
y= -4
I hope this helps!