Nathan K.
asked 10/30/16Please peform the indicated operation
(6x3 − 32x2 + 30x + 36) ÷ (x2 − 6x + 9)
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3 Answers By Expert Tutors
Inactive Tutor answered 10/30/16
Tutor
New to Wyzant
If we factor the divisor, we get
(x - 3)(x - 3)
This gives us a root of 3.
Divide the coefficients of the cubic factor by 3.
3 | 6 -32 30 36
18 -42 -36
____________________________
6 -14 -12 0
Then divide the coefficients of the quotient by 3 to get your answer.
3 | 6 -14 -12
18 12
________________________
6 4 0
The final quotient is then (6x + 4).
Inactive Tutor answered 10/30/16
Tutor
New to Wyzant
P(x)=6x3−32x2+30x+36
Q(x)=x2−6x+9
P(x) divided by Q(x) is:
P(x)Q(x)=6x+4
with the remainder of 0 .
X^2-6X+9
6X+4 Now Multiply
__________________
6X^3 -36X^2 +54X
+4X^2 -24X +36
____________________________
= 6X^3 -32X^2 +30X +36 -----> Checks
Inactive Tutor
Try Synthetic Division.,.sometimes helps
Report
10/30/16
Inactive Tutor answered 10/30/16
Tutor
New to Wyzant
(6x3 − 32x2 + 30x + 36) ÷ (x2 − 6x + 9)
6x - 26
_____________________
x2-6x+9 / 6x3 - 32x2 + 30x + 36 multiply by 6x
-(6x3 - 6x2 + 54x) subtract from original
--------------------------
-26x2 - 24x + 36 multiply by -26
-(-26x2 +156x-234) subtract
------------------------
-180x + 270 remainder
************************************
(6x3 − 32x2 + 30x + 36) ÷ (x2 − 6x + 9)
= 6x - 26 + (-180x+270)/(x2 -6x+9)
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Nathan K.
10/30/16