I do not understand how to solve this. Please help!

Question

^{The length of the rectangle is one more meter than 4 times its width. Find the dimensions if the perimeter is 52 meters.} 

Answer 1

Hi Cecilia,

 

Suppose width of a rectangle = x meter

          length woud be (4x+1) meters

 

perimeter of a rectangle = 2( length+ width)

substituting values,

                       52 = 2(4x+1 +x)

    dividing both sides by 2,

                       26= 5x+1

    subtracting 1 from both sides,

                        25=5x

                         x=5

4x+1= 4*5 +1= 20+1=21

 

Length of a rectangle = 21meters, Width of a rectangle= 5 meters

         

Answer 2

Let x = width

 

Then, 4x+1 = length

 

So, 2x + 2(4x+1) = 52

 

            10x+2 = 52

 

                 10x = 50

 

                    x = 5 meters

 

Width = x = 5 meters

length = 4x+1 = 21 meters