math help,equations, solve for Y

Question

Solve the equation for the indicated variable. (Assume a and b are positive real numbers.)

 

   

     y^2-ay+28by-28ab=0    for y

Answer 1

Since a and b are constants, we factor this like any other quadratic equation:

 

y² - ay + 28by - 28ab = y² - (a - 28b)y - 28ab = 0

(y - a)(y + 28b) = 0

y - a = 0 or y = a

 

and

 

y + 28b = 0

y = -28b