Gas Law Problem #4

Question

What pressure is required to compress 196.0 liters of air at 1.00 atmosphere into a cylinder whose volume is 26.0 liters? - Use an equation - Show All Work Please

Answer 1

Step 1: Identify the given values.

P₁ = 1.00 atm (initial pressure)

V₁ = 196.0 L (initial volume)

V₂ = 26.0 L (final volume)

P₂ = ? (final pressure)

Step 2: Use Boyle's Law.

Assuming temperature remains constant:

P₁V₁ = P₂V₂

Step 3: Solve for P₂.

P₂ = (P₁ × V₁) / V₂

P₂ = (1.00 × 196.0) / 26.0

P₂ = 196.0 / 26.0

P₂ = 7.53846 atm

Final answer: 7.54 atm

The pressure must increase to 7.54 atmospheres to compress the air from 196.0 liters to 26.0 liters at constant temperature.