1. Volume of a cylinder is πr2h, volume of a cone is (1/3)nr2h. the trick here is to treat r2h as though it was one value. So, 45n = nr2h means that r2h = 45. Now just plug that in to the cone formula.
2. Using the same formula as above for a cylinder, substitute factors of 2 and 3 in for each respective dimension:
If nr2h = 40 then when you substitute in 2r and 3h you get
n(2r)2(3h) = n(4r2)(3h) = 12nr2h
Now just use the original value you got from the question to get the answer.
3. This is similar to number two, use the formula for the volume of a cube and plug in the new dimensions to arrive at the answer:
Vcube = l3. The new V = (2l)3 = 8l3.
4. This one involves substituting the values given into the equation for the volume of a cone so that you are solving a single equation with one unknown:
(1/3)nr2h = 75n
You're given the radius so all that is left is to plug in the value and solve for h. hope that helped.