Solve and classify the given system of linear equations.

Question

{m=4(n+3)

{m=n-5

Answer 1

m = 4(n+5) = 4n +20

m = n - 5

 

To solve, set the two equations equal and solve for n:

 

4n + 20 = n - 5

3n = -30

n = -10

 

A system of equations that has exactly one solution (-10 in this case) is classified as "consistent and independent".