Scott H. answered • 07/06/16

Tutor

5
(1)
Engineering/Math/Science Tutor in Newmarket/Online

let a = length of first plane flight = 35 miles

let b = length of second flight = 20 miles

C is the angle between the paths = 42 degrees

c is the distance between the planes at the new point.

Law of Cosines: c

^{2}= a^{2}+ b^{2}- 2ab cos (C)= 35

^{2}+ 20^{2}- 2(35)(20) cos (42)= 1625 - 700 (0.7431)

= 1625 - 520.2

c

^{2 }= 1104.8c = √1104.8

c = 33.24 miles

The second part can be solved similarly with the two flight legs making the 'a' and 'b' legs of the triangle and the angle between them being angle 'C'