
Scott H. answered 07/06/16
Tutor
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Engineering/Math/Science Tutor in Newmarket/Online
let a = length of first plane flight = 35 miles
let b = length of second flight = 20 miles
C is the angle between the paths = 42 degrees
c is the distance between the planes at the new point.
Law of Cosines: c2 = a2 + b2 - 2ab cos (C)
= 352 + 202 - 2(35)(20) cos (42)
= 1625 - 700 (0.7431)
= 1625 - 520.2
c2 = 1104.8
c = √1104.8
c = 33.24 miles
The second part can be solved similarly with the two flight legs making the 'a' and 'b' legs of the triangle and the angle between them being angle 'C'