Science Question

Question

if Chris started running at 0m/s and ended with 2.9m/s, what is his acceleration? If his his mass is 82kg what is his force? His time is 2 hours

Answer 1

With the additional information, we can now answer the question.

 

Δt = 2 hours = 2(3600) s = 7200 s

 

a = Δv / Δt = [(2.9-0) m/s] / (7200 s) = 4.0278 x 10^-4 m/s²

 

F = ma = (82 kg)(4.0278 x 10^-4 m/s²) = 0.033028 N