James B. answered 06/03/16
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This can be worked using geometric sequences.
The base formula is ... an = a1 * rn - 1
where "a1" is the first term (8000) and "an"is the nth term, and "r" is the common ratio
We can substitute a1 =8000, a7 = 2800, and n=7, to solve for "r"
2800 = 8000(r)7-1
2800 = 8000(r)6
2800/8000 = r6 Divide by 8000 on both sides
.83948191 = r Take the 6th root of both sides
So our general formula for the nth term of the sequence is:
an = 8000(.83948191)n-1
Since we were instructed to round to the nearest album, I set an to .5 ... so when the term whittles down to .5 of an album, we want sales to stop at that point. When we substitute this in, we can solve for "n" to obtain the last term in the sequence. we could also set the value to 1 and get a slightly different answer. I was not sure which value to use. I chose .5.
.5 = 8000(.83948191)n-1
.5/8000 = .83948191n-1 Divide by 8000
.0000625 = .83948191n-1
ln (.0000625) = ln (.83948191)n-1 Take natural log of both sides
ln (.0000625) = (n - 1) * ln (.83948191) Log powers rule
ln (.0000625) = n * ln (.83948191) - ln (.83948191) Distribute
ln (.0000625) + ln (.83948191) = n * ln (.83948191) Solve for n
[ln (.0000625) + ln (.83948191)]/ln (.83948191) = n
n = 56.32
Thus it will take 56 weeks for the albums sales to fall to 1 album.
To find the number of albums sold, we use the formula for the sum of the first n terms of a geometric sequence
sn = a1(1 - r)n/(1 - r)
sn = 8000(1 - .83948191)56/(1 - .83948191)
sn = 49,836
Thus, 49,836 albums are sold in 56 weeks
Michael E.
11/28/16