
David O. answered 11/27/12
Masters Graduate and Long Time Personal Tutor
Polynomial long division is no different than regular long division. We begin by rewriting the original question into a more traditional division format:
(3x^4 – 6x^3 – 5x + 10) / (x – 2)
___________________
x – 2 | 3x^4 – 6x^3 – 5x + 10
Now that we have re-written the problem we can solve the problem by identifying what divisor (x – 2) can be multiplied by to solve:
_3x^3______________
x – 2 | 3x^4 – 6x^3 – 5x + 10
The first step is to find what the divisor can be multiplied by to equal the first part of the dividend (3x^4 – 6x^3). By multiplying x – 2 * 3x^3 we get 3x^4 – 6x^3, which we will subtract from the dividend leaving no remainder:
_3x^3______________
x – 2 | 3x^4 – 6x^3 – 5x + 10
3x^4 – 6x^3
0
We now bring down the remaining portion of the dividend (-5x + 10) and then multiply x – 2 by -5:
_3x^3______- 5________
x – 2 | 3x^4 – 6x^3 – 5x + 10
3x^4 – 6x^3 ↓
0 – 5x + 10
– 5x + 10
0
Once again there is no remainder, therefore the answer is 3x^3 – 5.
For the sake of argument, let us say there was a remainder. The solution would then be 3x^3 – 5 + the remained over the original divisor.