in triangle abc, a=6, b=3, and sin b= 1/4.

Question

What is the value of sin A?

Answer 1

We can use the Law of Sines to solve this which is that in triangle ABC,

a / sin A = b / sin B

In order to find sin A, we can start with the law of sines and plug in our values that are given:

a = 6, b = 3, and sin B = 1/4

6 / sin A = 3 / (1/4) Lets simplify this

6 / sin A = 12

sin A = 6 / 12

sin A = 1 / 2

So, the value of sin A = 1/2.

Answer 2

a/sinA =b/Sin B

6/sinA=3/ (1/3)

6/sinA = 9

sinA =6/9 =2/3

Answer 3

Your value of a is missing in your post, but use the law of sine to find sinA.

 

a / sinA = b / sinB