In this average problem, we see 3 examination scores of 70, 81, and 77.
We are told that the final examination is worth twice the regular scores.
There will be 5 exams, and the desired average is 85.
1. so, our equation becomes (70 + 81 +77 + 2x)/5 = 85
2. rearranging, 228 + 2x = 85 • 5, which becomes 2x = 425 - 228
3. solving for x, we 98.5
Proof: (70 + 81 +77 + 98.5 + 98.5)/5 = 425/5 = 85