A discussion of bearings is beyond the scope of this forum. The following site will help you understand the ideas.
Once you have made a diagram which represents the bearings, you will have a triangle, the hypotenuse of which will be 180m.
By subtracting 68o from 90o, you will get 22o. Then, by subtracting 90o from 150o, you will get 60o. The sum of 60o and 22o is 82o, the angle of the triangle which will be opposite the side of 180m. You will then be able to figure the other two angles, which are 30o and 68o.
Let side a be the side opposite angle A = 30o, and side b the side opposite angle B = 68o.
You can than use the Sine Law to calculate the lengths of the two sides.
a/sin A = c/sin C
a/ sin 30o = 180m/sin 82o So a ≅ 89m
b/ sin B = c/sin C
b/sin 68o = 180m/sin 82o So b ≅ 168m