Sam M.

asked • 04/02/16

Sequence and series

The value of n(sigma)i=1 i(Sigma)j=1 j(Sigma)k=1 =220, then the value of n is 
 
(*Sigma here is the summation sign) 
The options are 
11,12,10,9

1 Expert Answer

By:

Gregg O. answered • 04/02/16

Cal Poly Pomona engineering valedictorian, expert in geometry

Sam M.

There is 1 after j(Sigma)k=1 1=220,
We need to find the value of n
Report

04/02/16

Sam M.

This is the question 
n      i     j
Σ     Σ    Σ 1= 220
i=1 j=1  k=1
Report

04/02/16

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