What is the theoretical yield of CuO?

Question

What is the theoretical yield of CuO?

-Experimental yield of Copper II oxide-1.4
-Equation-CuCO3.Cu(OH)2 -->CuO + CO2+H2O

Answer 1

the balanced chemical equation that we're starting with here is

CuCO3​ ⋅ Cu(OH)2​ → CO2 ​ + H2​O + 2CuO

meaning that the mole ratio is 1 mole CuCO3: 2 moles of CuO

next then i would determine the moles of CuCO3 by dividing the given mass by the molar mass

Moles = 1.01 g / 221.114 g/mol = 0.004568 mol CuCO3

using the mole ratio that becomes

Moles of CuO = 0.004568 mol CuCO3 x 2 mol CuO / 1 mol CuCO3 = 0.009136 mol CuO

the last step then is multiplying that value by the molar mass

0.009136 mol CuO x 79.545 g/mol = 0.727 g

meaning that you end up producing approximately 0.727 grams of CuO for the theoretical yield in this scenario

Answer 2

I have no idea from where this question came, but there is no need to perform any calculation as the reaction described here will not occur.

 

The radical (OH)^-1 is much more electronegative than the (CO3)^-2 radical, so no displacement will occur.

 

Furthermore, neither of these compounds are soluble in water.

To illustrate the difference in stability, the solubility constant of cupric carbonate is 1.4x10^-10, but for cupric hydroxide, it is 2.2x10^-20