
James S. answered 03/03/16
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Advanced chemistry is my specialty, helping students is my passion
Hello Alex,
If you look at the whole question, a clue to the answer to part A is given in part B: "the sugar solution" implies that the sugar was dissolved in something, almost certainly water. Sand, of course, is not soluble in water, so that gives you a method of getting the sugar away from the sand (don't forget to dry the sand before you weigh it).
The real answer to part B is not "get rid of the water from the sugar solution," but instead you should apply the Law of Conservation of Mass. Since the original mixture was just sugar and sand, and you know how much of the mixture you had and how much sand was in it, a quick subtraction will give you how much must have been sugar.
Percent composition is a simple calculation:
% of a component = (mass of component)/(total mass)×100
Use that formula for the sugar and the sand, and you have the percent composition for the mixture.
Jim Scripko