find two consecutive even integers so that three times the smaller is 40 more than two times the larger

Question

 find two consecutive integers so that three times the smaller is 40 more than twice times the larger

 

Answer 1

Hi Jessica,

Step One: Create Let Statements

Let x= 1st even integer

Let x+2=2nd even integer

Step Two: Create an equation

3x=40+2(x+2) Distribute

3x=40+2x+4 Combine like terms

3x=44+2x Subtract 2x from both sides

3x-2x=44 Combine like terms

x=44

∴The first consecutive even integer is 44 while the second consecutive integer is 46.

Best, 

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