
David W. answered 02/11/16
Tutor
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This is a D-I-R-T (Distance-Is-Rate-times-Time) problem. [D=RT]
When the second car “catches” the first, the distance traveled by the two cars is the same.
Let T=0 when the first car starts.
The second car starts at T=2.
Find the value of T when the cars meet.
Distance: First Car Second Car
(39 mph)*(T) = (63)*(T-2)
The math:
39T = 63T -126
126 + 39T = 63T [add 126 to both sides]
126 = 24T [subtract 39T from both sides]
T = 5 1/4 hours
The second car “catches” the first at 2:15 p.m.