Let u= x+3

Question

(X+3)^2+27 (x+3)+26=

Answer 1

The question as stated is a little incomplete but I am going to assume that the problem is 'find the solutions of f(x)=(x+3)² + 27(x+3) + 26'.

 

Let u= x+3 and substitute into original equation. f(u)=u² + 27u + 26. 

Factor and f(u)=(u + 26) (u + 1) therefore either u + 26 = 0 or u + 1 =0

Add -26 to both sides of the first solution and you get u=-26

Add -1 to both sides of the second solution and you get u=-1

Substituting x + 3 in for u yields x + 3=-26 or x + 3=-1. Adding -3 to both sides of each.

x=-29 or x=-4.

 

Hope this was the question. 

0 0

Let u= x+3

Answer 2

Latianna,

I'm guessing you have already substituted x+3 for (u)

Now start by writing out the (x+3)^2 to make the steps easier to follow then go through using the proper order of operations...


[(x+3)(x+3)]+27(x+3)+26=

[x^2+6x+9]+27x+81+26

x^2+33x+116

 

This new answer can be factored since 4 X 29=116 and 4+29=33

 

(x+4)(x+29)